Complicated scores
I just came across this score.
I counted the highest beam to be 14, and that would mean a 49536th note. Surely that's not right?
Obviously there's other things - I couldn't possibly go into it!
Is any notation software able to handle this?
Comments
Quite amusing, actually! (It's a joke!?)
And the correct number for 14 flags is 256k (262144).
In reply to Amusing by schepers
More info : http://lostinthecloudblog.com/2010/03/13/john-stump-composer-of-faeries…
In reply to More info : by [DELETED] 5
I should have researched it more ;).
In reply to I should have researched it by chen lung
It is certainly a beautiful looking score and it is possible to read it for hours!
I wonder if anyone has attempted a performance - although it would be more of an improvisation.