Arpeggio doesn't work on semi-quavers or lower values

• Jun 21, 2010 - 02:18

Just as the subject says :).

I'm using a Mac 10.4.11 - MuseScore 0.9.6.

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• Jun 25, 2010 - 22:02

I've attached a bit of the track and its transcription (94 BPM). It's really a quaver in length, but I'm forced to divide it into a tied set of semi-quavers because of the bar lap.

Upon testing the software again, the lowest value it will playback correctly is actually a dotted semi-quaver (in certain instances - it didn't happen once).

A suggestion (if you wanted to implement a limit) is arpeggios beginning with values less than a dotted semi-quaver should only work if they're tied (and everything else is left to the wise discretion of the user).

Attachment Size
SK.zip 174.51 KB

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• Jul 26, 2010 - 10:55

As I said before it's by design. If the number of notes in a chord * the length of 32nd note is greater than the length of the chord then the arpeggio is not played. There is no logic for tied notes. That's why with a 2 16th note chord, there is no arpeggio.
All arpeggiated notes are played as a 32nd note offset in the other case, whatever the duration of the chord is. If you have an idea for a better algorithm in next version, speak out.

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• Jul 26, 2010 - 14:01

Sorry, not sure I fully understand.

The music I have requires a tied note because it goes into another bar (it is the length of a 8th note otherwise). Have you looked at the .ZIP file?

If it's a problem, can we file a report (so that we can introduce an algorithm - if that's what's needed)?

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